Question

in how many ways the word ARRANGE can such that 2'R's do not come together​

Answer 1

Answer:

660

Step-by-step explanation:

Total no of arrangements possible=7!/2!2!=1260

Total no of arrangements in which Rs are together=6!/2!=360

Total no of arrangements in which 2 As are together=6!/2!=360

Total no of arrangements in which 2 As as well as 2 R’so are together= 5!=120

Therefore total no. of arrangements in which neither 2 As nor 2 Rs are together= 1260-360-360+120=660