in how many ways the word ARRANGE can such that 2'R's do not come together
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Answer:
660
Step-by-step explanation:
Total no of arrangements possible=7!/2!2!=1260
Total no of arrangements in which Rs are together=6!/2!=360
Total no of arrangements in which 2 As are together=6!/2!=360
Total no of arrangements in which 2 As as well as 2 R’so are together= 5!=120
Therefore total no. of arrangements in which neither 2 As nor 2 Rs are together= 1260-360-360+120=660
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