In how many ways these n people can make handshakes so that no two handshakes crosses each other. N would be even.
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See every people will do handshake with 1 of his hand and so total handshakes that took place we can simply use this formula n(n-1)/2 as the no of handshakes are in AP where n = no.of persons
so 91 x 2 = n² - n
⇒ n² - n - 182 = 0
⇒n² - 14n + 13n - 182 = 0
⇒ n(n - 14) + 13(n - 14) = 0
⇒(n - 14)(n + 13) = 0
so n = -13 or 14 so no. of persons can't be negative so no of persons is 14 ANSWER
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