Question

In how many ways we can form a committee of 7 people from 7 men and 7 women such that the difference between the number of men and women in the committee is always 3 *


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Answer 1

${❥}\fbox\red{A}\fbox\orange{N}\fbox\purple{S}\fbox\green{W}\fbox\blue{E}\fbox\pink{R}$

Required answer-:

Excluding the woman which is selected we have to select 3 members from the rest 15 

So total no. of ways = ¹⁴C3=$\frac{14×13×12}{3×2×1}$

=364

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