Question

in how many wayz can 4 letters b posted in 5 letter boxes???

Answer 1

$\huge{Hey Mate!!!}$


Here is ur answer ⏬⏬⏬⏬⏬

❇➡ Number of letters = 4

 

Number of letter boxes = 5

 

Number of ways to place the first letter = 5

 

Number of ways to place the second letter = 5

 

Number of ways to place the third letter = 5

 

Number of ways to place the fourth letter = 5

 

Thus, by the multiplication principle of counting,  total number of required ways = 5 × 5 × 5 × 5 = 54

 

Cheers!!!!

Answer 2

HEY MATE HERE IS YOUR ANSWER

=> since the capacity of each letter box is not mentioned so we take it has infinite capacity

=> there are 5 letter boxes

=> for the first letter there are five options to put in a letterbox similarly for other 4

=> so, by fundamental principle of counting number of permutations => 5×5×5×5=5^4

=> alternately you can also take the rest of letters as set a and set of letter boxes as Saturday and then number of permutations is given by number of functions from A to B.

In this case n(B) - n(A)=4

So no of permutations

${5}^{4}$
Hope it will help you