Question

in how many year does the sum of 1200 rupes become 1800 rupes at the rate of simpal interest of 5%per annum​

Answer 1

Answer:

10 years

Step-by-step explanation:

P=1200 Rs, A= 1800Rs, R=5p.c.p.a To find: N(no. of yrs) I= A-P = 1800-1200=600rs . I =P×R×N/100 600= 1200× 5× N / 100 , 600= 60N ,N= 600/ 60= 10 years

Answer 2

$\Large{\textsf{\textbf{\underline{\underline{ 10 years . \::}}}}}$

Step-by-step explanation:

Given that:

• Sum = Rs 1200
• Amount = Rs 1800
• Rate of interest = 5% per annum

To Find:

• Time

Formula used:

• SI = A - P
• SI = (P × R × T)/100

Where,

• SI = Simple interest
• A = Amount
• P = Sum/Principal
• R = Rate of interest
• T = Time

First we have to find simple interest:

⇒ SI = A - P

⇒ SI = Rs 1800 - Rs 1200

⇒ SI = Rs 600

∴ Simple interest = Rs 600

Now finding the time:

⇒ SI = (P × R × T)/100

⇒ 600 = (1200 × 5 × T)/100

⇒ 600 = 6000T/100

⇒ 600 = 60T

⇒ T = 600/60

⇒ T = 10

$\small{\textsf{\textbf{\underline{\underline{∴ Time = 10 years\::}}}}}$