In how many year will a sum become double
of itself at 10% þ.e. by simple interest?
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Answer:
let the sum of money be p be =x
r = 10%
let the amount be 2x
si = a-p
2x-x=
x
now
t =100× si
p×r
= 100× x
x× 10
= 10 years
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