Question

In how many years a sum of Rs 30000 will amount to Rs. 45000 at the rate of 10% p.a simple interest​

Answer 1

Answer:

5 yrs

Step-by-step explanation:

A=45000

p=30000

s. I=15000

NO. OF YEARS=15000×100/30000×10

=5 YEARS

Answer 2

$\bf \: \underline{Given} :$ ↴

$\sf \: Principal = Rs. \: 30000$

$\sf \: Amount = Rs. \: 45000$

$\sf \: Rate = 10 \: \%$

$\bf \: \underline{To \: find} :$ ↴

$\sf \: First \: of \: all \: we \: have \: to \: find \: the \: simple \: interest.$

$\sf \: After, that \: we \: will \: find \: the \: time \: period.$

$\bf \: \underline{ \underline{Solution }}:$ ↴

$\boxed{ \red{\sf \: Simple \: interest = Amount - Principal}}$

$\implies \: \sf \: 45000 - 30000$

$\implies \: \sf \: 15000$

$\underline{ \sf \: So, \:Simple \: interest = Rs. \: 15000}$

$\sf \: Now,$

$\sf \: We \: will \: find \: the \: time \: period.$

$\sf \: As \: we \: know \: that,$

$\boxed{ \red{ \sf \: Simple \: Interest = \dfrac{P \times R \times T}{100} }}$

$\sf \: Where,$

$\longmapsto \: \sf \: P = Principal$

$\longmapsto \: \sf \: R = Rate \: of \: interest$

$\longmapsto \: \sf \: T = Time \: period$

$\sf \: Putting \: the \: values,$

$\implies \:\sf \: 15000 = \dfrac{30000 \times 10 \times T}{100}$

$\implies \:\sf \: 15000 = \dfrac{300000 \times T}{100}$

$\sf \: Cancel \: the \: zero's,$

$\implies \:\sf \: 15000 = 3000 \times T$

$\implies \:\sf \: \dfrac{15000}{3000} = T$

$\implies \:\sf \: \dfrac{15}{3} = T$

$\implies \:\sf \: 5 = T$

$\underline {\boxed{ \purple{\sf \: Therefore, \: the \: time \: period \: is \: 5 \: year's.}}}$