in how many years a sum will be twice of it at the rate of 20% per annum
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Let P= ₹ x. ,then A= 2.x. , S.I.= 2x - x = ₹ x. , R= 20% p.a. , T=?
(1) On simple interest:-
T = (S.I.×100)/(P×R) = (x.100)/(x.20) = 5.years. Answer.
(2). On compound interest:-
A= P.(1+R/100)^T.
or, 2.x = x.(1+20/100)^T.
or, 2. = (1.2)^T.
or, log 2. = T.log 1.2.
or, T = log 2/log 1.2 = 0.3010/0.0791. = 3.80 years. or, 3 years 9 months 18 days. Hope it helps. Please follow me
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