Question

in how many years does a sum of rs.10000 yield the simple interest of rs.1600 at the rate of 8% per annum?​

Answer 1

SOLUTION

GIVEN

A sum of Rs. 10000 yield the simple interest of Rs. 1600 at the rate of 8% per annum

TO DETERMINE

The number of years

EVALUATION

Here it is given that

Principal = P = 10000

Interest = I = 1600

Rate of interest = r % = 8 %

Time = T years =?

Now we are aware of the relationship that

$\displaystyle \sf{I = \frac{PRT}{100} }$

$\displaystyle \sf{ \implies \: 1600 = \frac{10000 \times 8 \times T}{100} }$

$\displaystyle \sf{ \implies \: T = \frac{1600 \times 100}{10000 \times 8} }$

$\displaystyle \sf{ \implies \: T = 2 }$

Hence the required time = 2 years

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Answer 2

Answer:

Given :-

• A sum of Rs 10000 yield is in the simple interest of Rs 1600 at the rate of 8% per annum.

To Find :-

• How many years.

Formula Used :-

To find time we know that,

$\boxed{\bold{\large{T\: =\: \dfrac{S.I\: \times 100}{P\: \times R}}}}$

where,

• T = Time
• S.I = Simple Interest
• P = Principal
• R = Rate of Interest

Solution :-

Given :

• Principal (P) = Rs 10000
• Simple Interest (S.I) = Rs 1600
• Rate of Interest (R%) = 8%

According to the question by using the formula we get,

⇒ $\sf T\: =\: \dfrac{1600 \times 100}{10000 \times 8}$

⇒ $\sf T\: =\: \dfrac{160000}{80000}$

⇒ $\sf T\: =\: \dfrac{\cancel{160000}}{\cancel{80000}}$

➠ $\sf\red{T\: =\: 2\: years}$

$\therefore$ The number of years is 2 years .