Question

in how many years does the sum of 1200 became 1800 at the rate of simple intrest of 5% per annum


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Answer 1

Answer:

• In 10 years the sum of Rs 1200 became Rs 1800 at the rate of simple interest of 5% per annum.

Step-by-step explanation:

Given that:

• Sum = Rs 1200
• Amount = Rs 1800
• Rate of interest = 5% per annum

To Find:

• Time

Formula used:

1. SI = A - P
2. SI = (P × R × T)/100

Where,

• SI = Simple interest
• A = Amount
• P = Sum/Principal
• R = Rate of interest
• T = Time

First we have to find simple interest:

⇒ SI = A - P

⇒ SI = Rs 1800 - Rs 1200

⇒ SI = Rs 600

∴ Simple interest = Rs 600

Now finding the time:

⇒ SI = (P × R × T)/100

⇒ 600 = (1200 × 5 × T)/100

⇒ 600 = 6000T/100

⇒ 600 = 60T

⇒ T = 600/60

⇒ T = 10

∴ Time = 10 years

Answer 2

$\Large{\textsf{\textbf{\underline{\underline{Given\::}}}}}$

• Principle (P) = Rs.1200

• Amount (A) = Rs.1800

• Rate of interest (R) = 5%

$\Large{\textsf{\textbf{\underline{\underline{To\:do\::}}}}}$

• The time period.

$\Large{\textsf{\textbf{\underline{\underline{Solution\::}}}}}$

As we know that,

✯ Formula to find Simple Interest (S.I) ✯

$\orange\bigstar\:{\Large\mid}\:{\textsf{\textbf{S.I\:=\: Amount\:-\: Principle\:}}}\:{\Large\mid}\:\green\bigstar$

➠ Simple interest = Rs.1800 - Rs.1200

➠ Simple interest = Rs.600

Again,

$\orange\bigstar\:{\Large\mid}\:{\bf{\purple{S.I\:=\:\dfrac{P\:R\:T}{100}\:}}}\:{\Large\mid}\:\green\bigstar$

Where,

• T = Time period

$\dashrightarrow\:\bf{600\:=\:\dfrac{1200\times{5}\times{T}}{100}\:}$

$\dashrightarrow\:\bf{6000\times{T}\:=\:600\times{100}\:}$

$\dashrightarrow\:\bf{6000\times{T}\:=\:60000\:}$

$\dashrightarrow\:\bf{T\:=\:\dfrac{60000}{6000}\:}$

$\dashrightarrow\:{\textsf{\textbf{\pink{T\:=\:10\: years}}}}$

∴ Time period is 10 years.

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