Math, asked by shivashankar1086, 10 months ago


In how many years does the sum of 1200
become 1800 at the rate of simple interest
of 5% per annum ?
(A) 10
(B) 20
(C) 15
(D) 25

Answers

Answered by ashimaarorapurvika
7

Answer:(a) 10

Step-by-step explanation:

SI = PRT/100

SI ==A-P

1800-1200=600

600=1200*5*X/100

600=60x

X=10

Hope u understood .

Pls mark as the brainliest ans...

Answered by itzBrainlystarShivam
1

\Large{\textsf{\textbf{\underline{\underline{(A) 10 years . \::}}}}} \\

Step-by-step explanation:

Given that:

  • Sum = Rs 1200
  • Amount = Rs 1800
  • Rate of interest = 5% per annum

To Find:

  • Time

Formula used:

  • SI = A - P
  • SI = (P × R × T)/100

Where,

  • SI = Simple interest
  • A = Amount
  • P = Sum/Principal
  • R = Rate of interest
  • T = Time

First we have to find simple interest:

⇒ SI = A - P

⇒ SI = Rs 1800 - Rs 1200

⇒ SI = Rs 600

∴ Simple interest = Rs 600

Now finding the time:

⇒ SI = (P × R × T)/100

⇒ 600 = (1200 × 5 × T)/100

⇒ 600 = 6000T/100

⇒ 600 = 60T

⇒ T = 600/60

⇒ T = 10

\small{\textsf{\textbf{\underline{\underline{∴  Time = 10 years\::}}}}} \\

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