Question

In how many years Rs 3,00,00 will be Rs 3,99,300 together with interest in 10% p.a. calculated compoundly​

Answer 1

Step-by-step explanation:

Amount=399300

p =300000

r=10%

$a = p(1 + \frac{r}{100} ) ^{n} \\ 399300 = 300000(1 + \frac{10}{100} ) {}^{n} \\ \frac{399300}{300000} = (\frac{10 + 1}{10} )^{n} \\ \frac{1331}{1000} = ( \frac{11}{10} ) {}^{n} \\ ( { \frac{11}{10}) }^{3} = ( { \frac{11}{10} )}^{n} \\ = n = 3 \: years$