Math, asked by jamadarrehan390, 3 months ago

*In how many years Rs. 6000 will amount to Rs 7986 at a compound interest rate of 10 %?*

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Answers

Answered by surbhi8542
20

Answer:

After 3 years the principal of 6000 amount to 7986

.Let after t years the principal of 6000 amount to 7986.

Principal = 6000

Rate of interest= 10%=0.1

Amount= 7986

The formula for amount is

A=P(1+r)^tA=P(1+r)

t

where, P is principal, r is interest rate and t is time in years.

7986=6000(1+0.1)^t7986=6000(1+0.1)

t

\frac{7986}{6000}=(1.1)^t

6000

7986

=(1.1)

t

\frac{1331}{1000}=(\frac{11}{10})^t

1000

1331

=(

10

11

)

t

(\frac{11}{10})^3=(\frac{11}{10})^t(

10

11

)

3

=(

10

11

)

t

On comparing both sides, we get

t=3t=3

Let after t years the principal of 6000 amount to 7986.

Principal = 6000

Rate of interest= 10%=0.1

Amount= 7986

The formula for amount is

A=P(1+r)^tA=P(1+r)

t

where, P is principal, r is interest rate and t is time in years.

7986=6000(1+0.1)^t7986=6000(1+0.1)

t

\frac{7986}{6000}=(1.1)^t

6000

7986

=(1.1)

t

\frac{1331}{1000}=(\frac{11}{10})^t

1000

1331

=(

10

11

)

t

(\frac{11}{10})^3=(\frac{11}{10})^t(

10

11

)

3

=(

10

11

)

t

On comparing both sides, we get

t=3t=3

Answered by shikhaprabhakar2203
0

Rs. 6000 will amount to Rs 7986 at a compound interest rate of 10 % in 3 years. Option (2) is correct.

Step-by-step explanation:

Principal Value is the value selected at a point in the domain of a multiple-valued function, chosen so that the function has a single value at the point.

Rate of interest is the annual rate that is charged for borrowing (or made by investing), expressed as a single percentage number that represents the actual yearly cost of funds over the term of a loan.

Time is the duration for which the amount has been borrowed.

Principal value = Rs 6000

Amount = Rs 7986

Rate of interest = 10 %

Time = t years

To calculate the find we need to put the values in the formula used for calculating compound interest.

A=P(1+\frac{r}{100} )^{t}

7986=6000(1+\frac{10}{100} )^{t}

\frac{7986}{6000}=(\frac{11}{10} )^{t}

\frac{1331}{1000} = (\frac{11}{10} )^{t}

(\frac{11}{10} )^{3}=(\frac{11}{10} )^{t}

Now by equating the powers we get,

t = 3

In 3 years the principal amount will be equal to Rs 7986.

By putting the given values in the formula we can conclude that option (1), (3), and (4) cannot be correct. Hence, option 2 is correct.

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