Math, asked by jyotirajranjan76, 2 months ago

in how many years rupees 20000 amounted to Rupees 24800 at 8% per annum
a.3yr
b.4yr
c.5ur
d.6yr​

Answers

Answered by shayaangenius1402
0

Answer:

The answer for this is 3 years

Step-by-step explanation:

Since we know SI = p*r*t

100

and SI = A-P

given,

P = 20000

A = 24800

R = 8 % p.a.

T = ?

Therefore,

SI = 24800-20000

SI = 24800-20000 = 4800

SI = 24800-20000 = 4800SI = 20000*8*t

SI = 24800-20000 = 4800SI = 20000*8*t 100

SI = 24800-20000 = 4800SI = 20000*8*t 1004800 = 20000*8*t

SI = 24800-20000 = 4800SI = 20000*8*t 1004800 = 20000*8*t 100

SI = 24800-20000 = 4800SI = 20000*8*t 1004800 = 20000*8*t 1004800 = 1600*t

SI = 24800-20000 = 4800SI = 20000*8*t 1004800 = 20000*8*t 1004800 = 1600*t4800 = t

SI = 24800-20000 = 4800SI = 20000*8*t 1004800 = 20000*8*t 1004800 = 1600*t4800 = t1600

SI = 24800-20000 = 4800SI = 20000*8*t 1004800 = 20000*8*t 1004800 = 1600*t4800 = t1600therefore after solving this we get the answer 3 .

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