in how many years rupees 20000 amounted to Rupees 24800 at 8% per annum
a.3yr
b.4yr
c.5ur
d.6yr
Answers
Answer:
The answer for this is 3 years
Step-by-step explanation:
Since we know SI = p*r*t
100
and SI = A-P
given,
P = 20000
A = 24800
R = 8 % p.a.
T = ?
Therefore,
SI = 24800-20000
SI = 24800-20000 = 4800
SI = 24800-20000 = 4800SI = 20000*8*t
SI = 24800-20000 = 4800SI = 20000*8*t 100
SI = 24800-20000 = 4800SI = 20000*8*t 1004800 = 20000*8*t
SI = 24800-20000 = 4800SI = 20000*8*t 1004800 = 20000*8*t 100
SI = 24800-20000 = 4800SI = 20000*8*t 1004800 = 20000*8*t 1004800 = 1600*t
SI = 24800-20000 = 4800SI = 20000*8*t 1004800 = 20000*8*t 1004800 = 1600*t4800 = t
SI = 24800-20000 = 4800SI = 20000*8*t 1004800 = 20000*8*t 1004800 = 1600*t4800 = t1600
SI = 24800-20000 = 4800SI = 20000*8*t 1004800 = 20000*8*t 1004800 = 1600*t4800 = t1600therefore after solving this we get the answer 3 .