Question

in how many years the amount for rs 10000 becomes rs 12100 at 10% compound in terest​

Answer 1

C.I.=P(1+R/100)^n

Here P = PRINCIPLE

R = RATE OF INTEREST

N = NO. OF YEAR

GIVEN:

P = 10000

C.I. =12100

R = 10%p.a.

n = ?

so put in equation

12100= 10000(1+10/100)^n

12100=10000(1+1/10)^n

12100= 10000(11/10)^n

12100/10000=(11/10)^n

121/100=(11/10)^n

(11/10)^2=(11/10)^n

as base are same of powers are:

2=n

so we have time = 2 YEARS

Answer 2

Answer:

solution, let the time =2 years

principal =10000

rate=10%

CA =p(1+r/100)^t

=10000(1+10/100)^2

=10000×1.1^2

=10000×1.21

=12100

hope it's helpful...