Question

*In how many years the amount for Rs. 10000 becomes Rs. 12100 at 10% compound interest?*

1️⃣ 1
2️⃣ 2
3️⃣ 3
4️⃣ 4​

Answer 1

$\huge\fcolorbox{cyan}{black}{Answer}$

❒ Compound Interest = P ( 1 + R/100 ) ^n

_______________

Let ,

✔ P - Principal

✔ R - Rate of interest

✔ N - No of years

------------------------

Given that:

• P - 10000
• Compound Intrest - 12100
• Rate - 10%
• N - ?

_________________

$❥Compound \: Interest = P ( 1 + \frac{R}{100} ) ^n$

$➮ 12100 = 10000( \frac{1 + 10}{100}) ^n$

$➭ 12100 = 10000 ( \frac{1 + 1}{10} )^n$

$➭ 12100 = 10000 ( \frac{11}{10} )^n$

$➭ \frac{12100}{10000} = ( \frac{11}{10} )^n$

$➭ \frac{11}{10} ^2 = ( \frac{11}{10} )^n$

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So value of N is 2.

➦ It will take 2 years.

Answer 2

Step-by-step explanation:

CompoundInterest=P(1+

100

R

)

n

➮ 12100 = 10000( \frac{1 + 10}{100}) ^n➮12100=10000(

100

1+10

)

n

➭ 12100 = 10000 ( \frac{1 + 1}{10} )^n➭12100=10000(

10

1+1

)

n

➭ 12100 = 10000 ( \frac{11}{10} )^n➭12100=10000(

10

11

)

n

➭ \frac{12100}{10000} = ( \frac{11}{10} )^n➭

10000

12100

=(

10

11

)

n

➭ \frac{11}{10} ^2 = ( \frac{11}{10} )^n➭

10

11

2

=(

10

11

)

n

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