Question

In how many years will ? 1,00,000 amount of
to 1, 33, 100 at 10% compound interest per annum​

Answer 1

Answer:

15.5 years

Explanation:

100000×T×10/100=133100

1000000×T=13310000

T=13310000/1000000

T=1331/100

T=13.31=15.5 mon

Answer 2

Given:

Principal (P) = 100000

Amount (A) = 133100

Rate of interest (R) = 10%

To find:

Time (n) = ?

We know the formula of amount (A)

$\boxed{\bf Amount = P(1+\frac{R}{100})^{n}}$

Now putting the given values,

$\bf \implies 133100 = 100000(1+\frac{10}{100})^{n}$

[Transporting 100000 to LHS]

$\bf \implies \dfrac{133100}{100000} =( 1+\dfrac{1}{10})^{n}$

Now, taking LCM = 10 in RHS

$\bf \implies \dfrac{133100}{100000} =( \dfrac{10+1}{10})^{n}$

$\bf \implies \dfrac{1331}{1000} =( \dfrac{11}{10})^{n}$

Now,

1331 = (11)³

And

1000 = (10)³

So,

$\bf \implies (\dfrac{11}{10})^{3} =( \dfrac{11}{10})^{n}$

Now bases are the same, equating their powers

Hence,

3 = n

Thus,

In 3 years the principal 100000 will amount to 133100 at 10% compound Interest per annum.