Question

In how many years will ₹2000 amount to ₹2163.20 at 4 %p.a compound annually​

Answer 1

what is Euclid's lemma ?

Answer 2

$Amount \: = \: P(1 + \frac{R}{100} )^t$

$Amount \: = \: P(1 + \frac{4}{100} )^t$

$2163.20 \: = \: 2000( \frac{26}{25} )^t$

$\frac{2163.20}{2000} \: = \: \frac{26}{25}^t$

$\frac{676}{625} \: = \: \frac{26}{25}^t$

$\frac{ 26^2 }{ 25^2 } \: = \: \frac{26}{25}^t$

$\frac{26}{25}^2 \: = \: \frac{26}{25}^t$

$on \: cancelling \:on$
$LHS \:and \:RHS$

$2 \: = \: t$

hence the answer is

${\huge{\boxed{\red{2 \:years}}}}$