Question

in how many years will 625 amount to 676 at 4 % per annum compound interest​

Answer 1

Answer:

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P= 625

A=676

R=?

T= 2 years

As we know

A=P(1+R/100)^9

$676 = 625( \times 1 + \frac{r}{100} ) ^{2}$

$\frac{676}{625} = (1 + \frac{r}{100} ) ^{2}$

$( \frac{26}{25} )^{2} = ( \frac{100 + r}{100} ) ^{2}$

$26 \times 100 = 2500 + 25r$

$25r = 2600 - 2500$

$r = \frac{100}{25} \\ = 4$

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