Question

In how many years will 8000 amount to 16000, if simple interest is earned at the rate of 12% per annum?​

Answer 1

Answer:

we all know that

I^2 =ptr/100 [ where i is interest, p is actual money , t is

so time and r is the percentage of interest]

8000= (8000× t ×12)/100

=> t =(8000×100)/(8000×12)

=> t =100/12

=> t = 25/3

Answer 2

Answer:

4¹/₆

Step-by-step explanation:

T = $\frac{100 * S.I}{PR}$

T = $\frac{100 * 8000}{16000 * 12}$

T = $\frac{100 * 1}{2* 12}$

T = $\frac{100}{24} = 4\frac{1}{6}$