Question

In how many years will a sum of $ 400 yield an interest of $ 132 at 11% per annum?

give appropriate answers pls

Answer 1

Answer:

3 YEARS.

Step-by-step explanation:

P = $ 400, R = 11% S.I = $ 132

T = (100 × S.I)/(P × R)

= (132 × 100)/(400 × 11)

= 3 years

Answer 2

Given :-

Principal = $ 400

Interest = $ 132

Rate = 11%

To Find :-

The time period

Solution :-

Considering simple interest ;

$Interest\: =\: {\dfrac{P\: \times\: R\: \times\: T}{100}}$

On inserting the values in the formula

We get ,

$132\: =\: {\dfrac{400\: \times\: 11\: \times\: T}{100}}$

=> 132 × 100 = 400 × 11 × T

$\implies\: T\: =\: {\dfrac{132\: \times\: 100}{400\: \times\: 11}}$

=> T = 3

Therefore, time period is 3 years

Short-hands Used :-

• P - Principal
• R - Rate
• T - Time
• I - Interest