Question

in how many years will a sum of money double it self at a rate of 8 % pa ​

Answer 1

Answer:

given

Let the principal (P) = ₹100

∴ Amount (A) = ₹100 × 2 = ₹200

∴ S.I. = A – P = ₹200 – ₹100

= ₹100

Rate (R) = 8% p.a.

∴ Time = (S.I. × 100)/(P × R) = (100 × 100)/(100 × 8)

= 25/2

= 12.1/2 Years. ans

hope itz hlp yu

Answer 2

Step-by-step explanation:

Consider the principle P=Rs.100

It is given A= 100×2 =Rs.200

We know that S.I=A−P

Substituting the values =200−100=Rs.100

Rate is given as R=8% p.a.

Here,

Time (T)=(S.I×100)/(P×R)

Substituting the values =(100×100)/(100×8)

=25/2

So we get =25/2=12(1/2) years