Math, asked by abhi1451, 11 months ago

in how many years will a sum of money double itself at 18.75% p.a. simple interest ?​

Answers

Answered by Anonymous
5

Let The Principal be x

R = 18.75%

T = y

A = 2x --------as the money doubles itself

A = P + I

2x = x + x*18.75*y/100 -----------[I = PRT/100]

2x = x + 18.75xy/100

2x - x = 18.75xy/100

x = 18.75xy/100

100x = 18.75xy

100 = 18.75y ----------------[Dividing x on Both The Sides]

100/18.75 = y

y = 5.3333 Years

y = 5 1/3 Years

y = 5 Years 4 Months

hope this answer helpful u


abhi1451: nice
abhi1451: wlcm bro
Answered by nalinsingh
1

Answer:

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