Math, asked by rupeshrkb3265, 1 year ago

in how many years will rs. 4000 amount to rs.4630.50 at 5% per annum, compound annually?

Answers

Answered by Anonymous
15
463050/100=4000(1+5/100)^n
9261/8000=(21/20)^n
(21/20)^3=(21/20)^n
so n=3
please mark it as a brainliest answer
Answered by Anonymous
92

\bold{\large{\underline{\underline{\sf{StEp\:by\:stEp\:explanation:}}}}}

→Amount = Rs. 4630.50

→Principal = Rs. 4000

→Rate = 5% p.a.

→Time = ?

So, simply by using the fromula of Amount of CI we can find the answer

\implies \tt{Amount = P \times \bigg(1 + \dfrac{r}{100} \bigg)^{t}}

\implies \tt{4630.50 = 4000 \times \bigg(1 + \dfrac{5}{100} \bigg)^{t}}

\implies\tt{\cancel\dfrac{46305}{10} = 4000 \times \bigg(1 + \cancel\dfrac{5}{100} \bigg)^{t}}

\implies \tt{\dfrac{9261}{2} = 4000 \times \bigg(1 + \dfrac{1}{20} \bigg)^{t}}

\implies \tt{\dfrac{9261}{2 \times 4000} = \bigg(\dfrac{20 + 1}{20} \bigg)^{t}}

\implies \tt{\dfrac{9261}{8000} = \bigg(\dfrac{21}{20} \bigg)^{t}}

\implies \tt{\bigg(\dfrac{21}{20} \bigg)^{3} = \bigg(\dfrac{21}{20} \bigg)^{t}}

\longrightarrow \boxed{\sf time = 3 \: yrs.}

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