Question

in how many years will Rs 6000 amount at Rs 7986 at 10% per annum compounded annually

Answer 1

A=7086
R=10%
P=6000
*=n=time

A=P(1+R/100)*
7986/6000=(11/10)*
7986/6000=1331/1000 = (11/10)``=(11/10)*
``=3
therefore,*=n=3
And = time is 3yrs.

Answer 2

Answer:

After 3 years the principal of 6000 amount to 7986.

Step-by-step explanation:

Let after t years the principal of 6000 amount to 7986.

Principal = 6000

Rate of interest= 10%=0.1

Amount= 7986

The formula for amount is

$A=P(1+r)^t$

where, P is principal, r is interest rate and t is time in years.

$7986=6000(1+0.1)^t$

$\frac{7986}{6000}=(1.1)^t$

$\frac{1331}{1000}=(\frac{11}{10})^t$

$(\frac{11}{10})^3=(\frac{11}{10})^t$

On comparing both sides, we get

$t=3$

Therefore, after 3 years the principal of 6000 amount to 7986.