in how many years will rs 6250 amount to rs 7290 at 8% per annum compounded annually
Answers
Answered by
33
Principal =₹6250
Amount =₹7290
Rate of interest =8%
Let the time be t years
According to the question
Amount =p(1+r/100)^t
6250×(1+8/100)^t=7290
(27/25)^t=7290/6250
(27/25)^t=(27/25)^2
t=2
Therefore =2 years..
Hope it helps u.
Pls mark my answer as brainliest.
In case of any doubt pls comment below.
Amount =₹7290
Rate of interest =8%
Let the time be t years
According to the question
Amount =p(1+r/100)^t
6250×(1+8/100)^t=7290
(27/25)^t=7290/6250
(27/25)^t=(27/25)^2
t=2
Therefore =2 years..
Hope it helps u.
Pls mark my answer as brainliest.
In case of any doubt pls comment below.
kyanhisamje:
thanks
Answered by
16
Principal (P) = ₹6250
Rate of interest (R) = 8% p.a
Amount = ₹7290
Lay Time be 'n' years

Time (n) = 2 years
Rate of interest (R) = 8% p.a
Amount = ₹7290
Lay Time be 'n' years
Time (n) = 2 years
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