Question

in how many years will rupees 1200 build on interest of rupees 200 at 4% S.I.?​

Answer 1

Step-by-step explanation:

Here,

P= ₹ 1200

R= 4%

S.I.= ₹200

Using the formula,

$s .i = \frac{p \times r \times t}{100}$

$200 = \frac{1200 \times 4 \times t}{100}$

$200 = 12 \times 4 \times t$

$200 = 48 \times t$

$t = \: \frac{200}{48}$

$t = 4 \frac{1}{6}$