Question

In how many years will the population
of a town be 209475 from 190000 at the growth rate of 5% per
annum?​

Answer 1

Answer:

given population of town=190000

population to reach=209475

rate=5%

we know,

$a = p {(1 + r \div 100)}^{n} \\ \: where \: n \: is \: the \: time \: period \\ p \: is \: the \: given \: population \: of \: the \: town \\ and \: a \: is \: the \: population \: to \: reach \: and \: r \: is \: the \: rate \: of \: population \: increase \\ now \: on \: putting \: value \: we \: get \\ 209475 = 190000 {(1 + 5 \div 100)}^{n} \\ 209475 \div 190000 = {(21 \div 20)}^{n}$

8379/7600={(3×7)/(4×5)}^n

$({3}^{2} \times {7}^{2} \times 19) \div ({4}^{4} \times {5}^{2} \times 19) = {(3 \times 7) \div (4 \times 5)}^{n} \\ {((3 \times 7) \div (4 \times 5))}^{2} = {((3 \times 7) \div (4 \times 5))}^{n}$

hence, n=2

The time period will be 2years

HOPE THIS WILL HELP YOU

जय महाकाल

Answer 2

Step-by-step explanation:

Given.

P=209475

P*t=190000

R=5%

T=?

Here,

P*t= P[(1+R÷100)*t]

209475=190000[(1+5÷100)*t]

209474÷190000=(1.05)*t

1.1025=(1.05)*t

(1.05)*2=(1.05)*t

T=2years

#Hope helpful to you ☺️#