In how many zeros are there in the expansion of 13 × 15 × 22 × 125 × 44 × 35 × 11
Answers
Answered by
1
Answer:
0 expansion
Step-by-step explanation:
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Answered by
2
Answer:
3 zeroes
Step-by-step explanation:
13 x 15 ( 3x5 ) x 22 ( 11x2 ) x 125 ( 5x5x5 ) x 44 ( 11x2x2 ) x 35 ( 5x7 ) x 11
So, here we have 5 = 5 times ( 5x5x5x5x5 ) and
2= 3 times ( 2x2x2 )
So maximum numbers of pairs of 5x2 are 3 times which makes 3 zeroes in the multiplication.
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