Math, asked by rameshroyy605, 3 months ago

In how many zeros are there in the expansion of 13 × 15 × 22 × 125 × 44 × 35 × 11 ​

Answers

Answered by veermalachauhan0141
1

Answer:

0 expansion

Step-by-step explanation:

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Answered by Harshil9798
2

Answer:

3 zeroes

Step-by-step explanation:

13 x 15 ( 3x5 ) x 22 ( 11x2 ) x 125 ( 5x5x5 ) x 44 ( 11x2x2 ) x 35 ( 5x7 ) x 11

So, here we have 5 = 5 times ( 5x5x5x5x5 ) and

                              2= 3 times ( 2x2x2 )

So maximum numbers of pairs of 5x2 are 3 times which makes 3 zeroes in the multiplication.

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