Question

In how much percentage surface area decreased when edge of cube is 50% less than initial length?

50
20
25
0076
lear Response
Next >>​

Answer 1

Answer:

Assume the initial value of edge was  x  

So, Initial Surface Area,  A1=6x2  

The edge increased by 50%, so, the final edge length is,  3x/2  

So, final Surface Area,  A2=6(3x/2)2=6(9x2/4)=6x2(9/4)=9/4(A1)  

So, Increase in Surface Area,  dA=A2−A1=9/4(A1)−A1=A1(9/4−1)=A1(5/4)  

So, the area increased by  5/4  

Now, percentage increase will be  (  5/4)∗100=125 %

So, the percentage increase in the Surface Area of the cube will be 125%.

Step-by-step explanation: