Question

In how much time will the interest on Rs. 800 at 12.5% per annum be Rs. 125?​

Answer 1

Answer:

The time required for Rs. 800 to give interest of Rs. 125 is 1.25 year.

Step-by-step explanation:

The sum of money = Rs. 800

Rate of interest = 12.5 %

Interest on the money = Rs. 125

Following the formula of Simple Interest,

$\bigstar \: \boxed{\sf{Simple \: Interest = \dfrac{Principle \times Rate \times Time}{100}}}$

• Principle = Rs. 800
• Time = T
• Rate = 12.5 %
• Simple Interest = Rs. 125

$\sf{\longrightarrow} \: 125 = \dfrac{800 \times 12.5 \times T}{100}$

$\sf{\longrightarrow} \: 125 = \dfrac{10000T}{100}$

$\sf{\longrightarrow} \: 125 \times 100 = 10000T$

$\sf{\longrightarrow} \: 12500 = 10000T$

$\sf{\longrightarrow} \: T = \dfrac{12500}{10000}$

$\sf{\longrightarrow} \: T = 1.25$

Time = 1.25 year

Therefore, the time required for Rs. 800 to give interest of Rs. 125 is 1.25 year.

Answer 2

Answer:

1.25years or 1year 3months

Step-by-step explanation:

Here,

Principle=P=800

Rate of Interest =R=12.5%

Interest=I=125

Time=T

We know that

$\boxed{\sf {\blue{\bigstar}}Interest=\dfrac{Principal\times Rate\:of\:Interest \times Time}{100}}$

$\\ \sf{:}\rightarrowtail 125=\dfrac{800\times 12.5\times T}{100}$

$\\ \sf{:}\rightarrowtail 125=\dfrac{10000T}{100}$

$\\ \sf{:}\rightarrowtail 12500=10000T$

$\\ \sf{:}\rightarrowtail T=\dfrac{12500}{10000}$

$\\ \sf{:}\rightarrowtail T=1.25years$

Therefore Time required is 1.25years or 1year 3months.