Question

In how much time will the simple interest on ruppes on 8000 at 25/2% per annum be added 250

Answer 1

$let \: \: time \: = t \\ si = \frac{p \times t \times r}{100} \\ atq \\ si = \frac{8000 \times t \times 25}{100 \times 2 } = 250 \\ when \: you \: will \: solve \\ si = 1000t \: = 250 \\ t = \frac{250}{1000 } \\ 0.25 \: is \: your \: answer$