Question

In how much time would ₹5000amount to ₹6655 at 10%per annum compound interest

Answer 1

Amount (A) = Rs 6655
Principal (P) = Rs 5000
Rate (R) = 10% p.a.

A= P(1+R/100)^N
=> 6655= 5000(1+10/100)^N
=> 6655/5000=( 110/100)^N
=> (1331/1000) = (11/10)^N
=> (11/10)^3 = (11/10)^N
Hence base is equal,
=> 3 years = N
or
=> N = 3 years

Be Brainly

Answer 2

Answer:

P=5000 Rs

C.I=1655 Rs

R=10percent P.a

T=?

C.I= A-P

1655=A-5000

A= 5000+1655

A=6655

A=P(1+R)÷100^N

6655=5000(1+10÷100)^N

6655=5000(10+1÷10)^N

6655=5000(11÷10)^N

6655÷5000=(11÷10)^N

1331÷1000=(11÷10)^N

11×11×11÷10×10×10=(11÷10)^N

11^3÷10^3=(11÷10)^N

(11÷10)^3=(11÷10)^N

HENCE, N=3 YEARS