Question

in how much time would be simple interest on a certain sum be 0.125 times the principal at 10% per annum

Answer 1

Let the principal/sum be x.

Given SI = 0.125 = 1/8 x, R = 10%. 

We know that Time = (100 * SI)/(P*R)

                                 = 100 * x/x * 8 * 10

                                 = 5/4 (or) 1 1/4 years.

Answer 2

Answer:

The time is $1 \frac{1}{4} \text { years }$.

Step-by-step explanation:

Simple interest exists interest calculated on the principal amount of a loan or the original contribution to a savings account. Simple interest does not compound, suggesting that an account holder will only earn interest on the principal, and a borrower will never carry to pay interest on interest already accrued.

Given that,

Interest on a certain sum be 0.125 times the principal at 10% per annum

To find,

in how much time would be the simple interest on a specific sum be 0.125 times the principal at 10% per annum.

Let Sum = x

Then,

$&\mathrm{S} . \mathrm{I}=0.125 \mathrm{x}=\frac{1}{8} \mathrm{x}$

$&\mathrm{R}=10 \%$

Time $&=\frac{100 \times x}{x \times 8 \times 10}$

$&=\frac{5}{4}$

$&=1 \frac{1}{4} \text { years }$

Hence, The answer is$1 \frac{1}{4} \text { years }$.

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