in how much time would the simple interest on a certain sum be 0.125 times the principal at 10% per annum
Answers
Answered by
12
let p be x
si=0.125x
=125x/1000
si=prt/100
=125x/1000=x×10×t/100
=12500x/10000x=t
=0.0125yrs
pls mark my answer as brainliest if it helps you
si=0.125x
=125x/1000
si=prt/100
=125x/1000=x×10×t/100
=12500x/10000x=t
=0.0125yrs
pls mark my answer as brainliest if it helps you
Answered by
0
Answer:
Step-by-step explanation:
let p be x
si=0.125x
=125x/1000
si=prt/100
=125x/1000=x×10×t/100
=12500x/10000x=t
=0.0125yrs
pls mark my answer as brainliest if it helps you
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