In hydrogen atom, an electron jumps from
bigger orbit to smaller orbit so that radius
of smaller orbit is one-fourth of radius of
bigger orbit. If speed of electron is bigger
orbit was v, the speed in smaller orbit is
V
A
2.
V
2v
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Answer:
Radius of nth orbit,
r
n
∝
n
2
rn∝n2
r
n big
r
n small
=
n
2
big
n
2
small
=
4
1
rn bigrn small=n2bign2small=41
(given)
Rightarrow
n
big
n
small
=2
nbignsmall=2
Rightarrow
n
small
n
big
=
1
2
nsmallnbig=12
Velocity of electron in nth orbit
v
n
∝
1
n
vn∝1n
v
(n big)
v
(n small)
=
n
small
n
big
=
1
2
v(n big)v(n small)=nsmallnbig=12
Rightarrow
V
n small
=2(
v
n big
)=2v
Explanation:
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