Question

In hydrogen atom, an electron undergoes transition from 3rd excited state to the first excited state and then to the ground state. Identify the spectral series to whitransitions belong.​

Answer 1

Answer:

Explanation:

According to Bohr, when an electron from its initial stationary orbit with n=ni​ jumps to another (lower) stationary orbit with n=nf​, it emits energy equal to the difference between the energy of the two stationary orbits in the form of small packets of light known as photons. For every transition of the electron, there is a line in the spectrum and there are different types of spectral series formed. He gave the spectrum of Hydrogen ion which has one electron only, so this spectrum cannot be applied for atoms with more than one electron. The following are the series in the hydrogen spectrum: –

a)      Lyman Series: – when the electron jumps from any higher stationary orbit to first stationary orbit, the spectral lines falls in the Lyman series. For Lyman series, ni​=1.

Now putting nf​=1 in the relation given by Bohr,w=Rh​(121​−ni2​1​), ni​=2,3,4....

b)      Balmer Series: – when the electron jumps from any higher stationary orbit to the second stationary orbit with nf​=2, the spectral lines falls in the Balmer Series. Here, ni​=2

w=Rh​(221​−ni2​1​), ni​=3,4,5....

c)       Paschen Series: – when the electron falls from any higher stationary orbit to third stationary orbit with n=3, the spectral lines falls in the Paschen Series. Here nf​=3

w=Rh​(321​−ni2​1​), ni​=4,5,6....

d)      Brackett Series: – when the electron jumps from any higher stationary orbit to fourth stationary orbit with n=4, the spectral lines fall in Bracket Series. Here, nf​=4

w=Rh​(421​−ni2​1​), ni​=5,6,7....

e)      Pfund Series: – when the electron from any higher stationary orbit jumps to fifth stationary orbit with n=5, the spectral lines falls in Pfund Series. Here, nf​=5

w=Rh​(521​−ni2​1​), ni​=6,7,8....

Answer 2

Answer:

The transition belongs to the Balmer and Lyman series.

Explanation:

CASE A: From third exited state to first excited state

For this transition to occur the quantum states are as follows,

n₁=2               (first excited state)

n₂=4               (third excited state)

For the Balmer series, we know that the electronic transition takes place from a higher energy state to an n=2 energy state.

So, this transition series belongs to the Balmer series.

CASE B: From first excited state to ground state

For this transition to occur the quantum states are as follows,

n₁=1               (ground state)

n₂=2            (first excited state)

For the Lyman series, we know that the electronic transition takes place from a higher energy state to an n=1 energy state.

So, this transition series belongs to the Lyman series.

Hence, the transition is part of the Balmer and Lyman series of transitions.

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