in hydrogen atom electron is moving in a circular orbit of radius 5.3x 10^-11 metre with speed of 2.3x10^4 metre per second find magnetic moment of revolving electron??
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Answer:
magnetic moment of revolving electron is =6.91×10^13
Explanation:
v= 2.3× 10^4 meter
r= 5.3× 10^-11 meter
formula,
v= r.w = r× 2π/T
T= 2πr/v
T= (2 × 3.14 × 5.3×10^-11)/ (2.3×10^4)
T= 1.44 × 10^-14
Now, f= 1/T
f= 1/(1.44 × 10^-14) =6.91×10^13
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