Question

In hydrogen atom energy difference between the states n=2 and n=3 is E eV. the ionization potential of H atom is-- 1) 3.2 E 2) 5.6 E 3) 7.2 E 4) 13.2 E​

Answer 1

Explanation:

Energy difference= E=Eo[(2)21−(3)21]=365Eo

⇒Eo=7.2E

Ionization potential=E1=Eo[(1)21−∞1]=Eo

∴E′=7.2E

Answer 2

Answer:

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