Chemistry, asked by JayBhagat5227, 11 months ago

In hydrogen atom energy in 2nd Bohr's orbit is -3.4 eV .The kinetic energy of electron in this orbit is

Answers

Answered by Draxillus

1

Heya,

The kinetic energy of electron will be 3.4 eV.

In Bohr's orbit, K.E. = mod(T.E.)

Regards

Kshitij

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