Question

In hydrogen atom energy of first excited state is -3.4 electron volt. Find ke and pe of the electron in ground state

Answer 1

Explanation:

The ground state energy of hydrogen atom is -13.6eV. (i) What is the kinetic energy of an electron in the second excited state ? (ii) If the electron jumps to the ground state from the second excited state, calculate the wavelength of the spectral line emitted.

Answer 2

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The ground state energy of hydrogen atom is -13.6eV.

• (i) What is the kinetic energy of an electron in the second excited state?
• (ii) If the electron jumps to the ground state from the second excited state, calculate the wavelength of the spectral line emitted.