Chemistry, asked by rahulparmarn6894, 11 months ago

In hydrogen atom energy of first excited state is -3.4 thenfind out ke

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Answered by ritwikkumarjagwani

Answer:

KE = 3.4 eV . it's simple

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ritwikkumarjagwani: ok

ritwikkumarjagwani: from where do u blong?

spotdukheviiia89: Pune, Maharashtra

spotdukheviiia89: n u?

ritwikkumarjagwani: ptna, bihar

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ritwikkumarjagwani: ok

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ritwikkumarjagwani: all the best

spotdukheviiia89: thanks a lot

Answered by spotdukheviiia89

Hey mate,

Total energy= -3.4

Hence, K.E = 3.4J

Hope it helps you

ritwikkumarjagwani: how

ritwikkumarjagwani: will u explain

spotdukheviiia89: it's been taught to us the same way ie- if we just take off the negative sign from the Total energy we get K.E

spotdukheviiia89: mark it as brainliest please

ritwikkumarjagwani: ya it is

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