In hydrogen atom energy of first excited state is -3.4 thenfind out ke
Answers
Answered by
1
Answer:
KE = 3.4 eV . it's simple
Attachments:
![](https://hi-static.z-dn.net/files/d61/9f06f3c9f22bf15fa4c024edbd88c74f.jpg)
ritwikkumarjagwani:
ok
Answered by
0
Hey mate,
Total energy= -3.4
Hence, K.E = 3.4J
Hope it helps you
Similar questions