Question

In hydrogen atom, energy of first excited state is -3.4 eV. Then find out KE of same orbit of hydrogen atom
(1) +3.4 eV
(2) +6.8 eV
(3) -13.6 eV
(4) +13.6 eV​

Answer 1

Answer:

kinetic energy will be negative of total energy.

therefore kinetic energy=+3.4 eV