Question

in hydrogen atom energy of the first excited state is -3.4 electron volt then find out the kinetic energy of the same orbit of hydrogen atom.

Answer 1

Answer:

For example an electron in the ground state has an energy of -13.6 eV. The second energy level is -3.4 eV. Thus it would take E2 − E1 = -3.4 eV − -13.6 eV = 10.2 eV to excite the electron from the ground state to the first excited state.

Explanation:

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Answer 2

This is the answer below