In hydrogen atom, the de Broglie wavelength of an
electron in the second Bohr orbit is
[Given that Bohr radius, a, = 52.9 pm]
(1) 105.8 pm
(2) 211.6 pm
(3) 211.6 n pm
(4) 52.9 n pm
Answers
Answered by
67
QUESTION :-
In hydrogen atom , the debroglie wavelength of an electron in the second bohr orbit is [Given that the radius of first Bohr orbit is 52.9 pm ]
(1) 105.8 pm
(2) 211.6 pm
(3) 211.6π pm
(4) 52.9π pm
GIVEN :-
- An electron is present in second bohr orbit of hydrogen
TO FIND :-
- Debroglie-wavelength of the electron in second bohr orbit of hydrogen
SOLUTION :-
Radius of nᵗʰ orbit in pm is given by
Where ,
- rₙ is Radius of nᵗʰ orbit
- n is number of the orbit
- z is atomic Number
we want the Radius of the Second bohr orbit in hydrogen ,
so ,
- Z = 1
- n = 2
Relation between bohr theory and debroglie theory is given by ,
Where ,
- n is orbit number or Number of waves
- λ is wavelength
- r is radius
ADDITIONAL INFO :-
★ Debroglie wavelength when mass and velocity are given is given by ,
Where ,
- h is planck's constant
- m is mass
- v is velocity
★ Debroglie wavelength when mass and kinetic enery are given is given by,
Where ,
- h is planck's constant
- m is mass
- KE is kinetic energy
Answered by
17
Answer:
211.6 pie pm
Explanation:
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