Chemistry, asked by Sandipan1265, 7 months ago

In hydrogen atom, the de Broglie wavelength of an
electron in the second Bohr orbit is
[Given that Bohr radius, a, = 52.9 pm]

(1) 105.8 pm
(2) 211.6 pm
(3) 211.6 n pm
(4) 52.9 n pm​

Answers

Answered by Mysterioushine
67

QUESTION :-

In hydrogen atom , the debroglie wavelength of an electron in the second bohr orbit is [Given that the radius of first Bohr orbit is 52.9 pm ]

(1) 105.8 pm

(2) 211.6 pm

(3) 211.6π pm

(4) 52.9π pm

GIVEN :-

  • An electron is present in second bohr orbit of hydrogen

TO FIND :-

  • Debroglie-wavelength of the electron in second bohr orbit of hydrogen

SOLUTION :-

Radius of nᵗʰ orbit in pm is given by

\large\rm {\bold{\boxed{ \bigstar{ | \: r_n\:=\:\frac{n^2}{z}\times\:52.9 \: pm |}}}}

Where ,

  • rₙ is Radius of nᵗʰ orbit
  • n is number of the orbit
  • z is atomic Number

we want the Radius of the Second bohr orbit in hydrogen ,

so ,

  • Z = 1
  • n = 2

 :  \implies \:  r_{2} \:  =  \frac{ ({2})^{2} }{1}  \times 52.9 \: pm\\  \\  :  \implies \: r_{2} \:   =  \frac{4}{1}  \times 52.9  \: pm\\  \\  :  \implies \: r_{2} \:  = 4 \times 52.9  \: pm\\  \\  :  \implies   {\bold {\boxed {\: r_{2} \:  = 211.6 \: pm}}}

Relation between bohr theory and debroglie theory is given by ,

\large\rm {\bold{\boxed{ \bigstar{ | n \lambda = 2\pi  r |}}}}

Where ,

  • n is orbit number or Number of waves
  • λ is wavelength
  • r is radius

 :  \implies \: (2)( \lambda) \:  = 2 \times   \: \pi  \times 211.6 \: pm \\  \\   : \implies \lambda \:  =   211.6 \pi  \: \: pm

\large \dag { \:  \: Hence ,\: option(c) \: is \: correct}

ADDITIONAL INFO :-

★ Debroglie wavelength when mass and velocity are given is given by ,

 \large \underline{ \bold {\boxed  {   \lambda \:  =  \frac{h}{mv} }}}

Where ,

  • h is planck's constant
  • m is mass
  • v is velocity

★ Debroglie wavelength when mass and kinetic enery are given is given by,

\large\underline\bold{\boxed{\lambda\:=\:\frac{h}{\sqrt{2mKE}}}}

Where ,

  • h is planck's constant
  • m is mass
  • KE is kinetic energy
Answered by 123abc22
17

Answer:

211.6 pie pm

Explanation:

pls find the solution in the image attached

hope it helps

Attachments:
Similar questions