Chemistry, asked by Sajalsharma5, 9 months ago

In hydrogen atom the de Broglie wavelength of an electron in the second bohr orbit is

Answers

Answered by bsrsyamala

0

Answer:

2pi r/3

Explanation:

Formula is n lambda=2pi r

Lambda=de Broglie wavelength

n=orbit number

So now,

Lambda=2pi r/3

Hope it helps

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