Question

In hydrogen atom the electron revolves around the
proton at a speed of 2.18×10^6 m/s in a circle of
radius 5.28 x 10-11 m. Calculate the acceleration of
the electron and compare it with the acceleration due
to gravity.
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Answer 1

Answer:

ans: 9.0 × 1022 m/s² = 1022

Explanation:

as ac = v²/r = (2.18 × 10⁶)²/ 5.28 × 10 minus ¹¹

= 0.9 × 10 ¹² plus ¹¹

= 0.9 × 10²³

= 9 × 10²²

hope it would helpful