Question

In hydrogen atomic spectrum, a series limit is found at 12186.3 cm⁻¹. Then it belong to
(a) Lyman series
(b) Balmer series
(c) Paschen series
(d) Brackett series

Answer 1

Wave no. = R[1/(n1)2 - 1/(n2)2]

12186.3 = 109677[1/(n1)2]

(n1)2×12186.3= 109677

Therefore (n1)2 = 109677/12186.3

(n1)2 = 9

So n1 = 3 so it is paschen series

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Answer 2

Answer: D

Brackett series

Explanation:

Becase

n=4.5 approx. Sso n=4