In hydrolic lift the diameter of the piston P2 is 50 cm and that of piston P1 is 10 cm .What is the force exerted on P2 when a force of 1N is applied on P1?
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Answered by
4
Answer:
since pressure applied in closed liquid is transferred throughout the liquid theirfore force/area=constant
area of piston P1 and piston P2 who is π{10×10) and π(50×50) and forces required on piston P1 and piston P2
be X and 1N and by using the formula force X area is equal to constant and putting the respective reading values 1/{π×50×50)=X/(π×10×10)
value of X come out to be .04 N (attention I have not converted centimetre into metres because even if you convert them the 10^-2 will automatically cancel out on both sides)
Answered by
7
Answer:25N
Explanation:
(=50/10)^2
=2500/100
=25N
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