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i) 4.x + y=34; x+4y= 16
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Answer:
(4x+y=34)*4 ...(i)
(x+4y=16)*1 ...(ii)
Subtrating (ii) from (i)
16x+4y=136
x+4y=16
(-) (-) (-)
15x = 120
x=8
Putting x=8 in (i)
4x+y=34
4*8+y=34
32+y=34
y=2
Therefore, x=8 & y=2
:) :)Step-by-step explanation:
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