Math, asked by jaibahadurrai1956, 5 months ago

in
i) 4.x + y=34; x+4y= 16​

Answers

Answered by rishaanbhojwani
3

Answer:

(4x+y=34)*4 ...(i)

(x+4y=16)*1 ...(ii)

Subtrating (ii) from (i)

16x+4y=136

x+4y=16

(-) (-) (-)

15x = 120

x=8

Putting x=8 in (i)

4x+y=34

4*8+y=34

32+y=34

y=2

Therefore, x=8 & y=2

:) :)Step-by-step explanation:

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